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A sample of 57 research cotton samples resulted in a sample average percentage elongation of 8.16 and a sample standard devia

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Answer #1

Solution: Given that n = 57, x = 8.16, sd = σ = 1.45

95% Confidence interval for Z = 1.96

95% Confidence interval for the average mean = X +/- Z*s/sqrt(n)
= 8.16 +/- 1.96*1.45/sqrt(57)
= (7.784 , 8.536)

=> option A.

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