Question

You throw a rock straight up and it returns to your hand with the samc vertical speed you gave it. Up is positive and down is negative. Distance is measured from your hand a. Draw the rocks position vs. time graph on the left-hand axes b. Draw the rocks velocity vs. time graph on the middle axes c. Draw the rocks acceleration vs. time graph on the right-hand axes.4. The motion of a train traveling on a straight track has the velocity versus time graph shown a. Determine the total distance the train travels. There is more than one way to do this Try using a graphical approach. Answer: 574 meters b. Determine the acceleration of the train during the first 10 seconds of its motion c. Determine the trains acceleration at t 20 s d. Determine the acceleration of the train during the last 20 seconds of its motion 20 m/s 10 m/s

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3. We know that, "Up" is positive and "Down" is negative.

(a) Draw the rock's position vs. time graph on the left-hand axes.

(b) Draw the rock's velocity vs. time graph on the middle axes.

(c) Draw the rock's acceleration vs. time graph on the right-hand axes.

Answer of all three above questions which can be shown below as -

Position in m) Velocity in m/s Acceleration (in m 0 0 0 Time [in sec) Time (in sec) Time (in sec)

4. The motion of a train traveling on a straight track has the velocity versus time graph shown.

(b) During the first 10 seconds of its motion, an acceleration of the train which will be given by -

a = Deltav / Deltat

a = [(14 m/s) - (0 m/s)] / [(10 s) - (0 s)]

a = [(14 m/s) / (10 s)]

a = 1.4 m/s2

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