Question

Copper(t) bromide reacts with magnesium metal: 2 CuBr + Mg + 2 Cu + MgBr2 If 0.253 moles of magnesium react in this way, a. How many grams of CuBr are consumed? (1 point) . 143.45 g/mol 0,50cmol x 143.45 g/mol 0.295 mol cu Br x2-0.50 mo = 72.58 grams b. How many grams of Cu can be produced? (1 point), 2x 0.253 moly. 63.596 g/mol = 3 Zoltaron

Answer 1

ANS Given reaction 2 cuBr +mg - acut Mg Bry le 2 m de cubr reals with 'ng' to produce 2 mole ce and i mole "mg Bry". If 0.283 moles of 'ng' realt @ How many grams of cuber ale consumed I mole cubr = 1 Mole mg ? mole cubr = 0.253 mole mg . I molo cubr x 0.253 Mole Mg I mote Tig = 0.506 mole cubr consumed. calculate the mass of Cabr

calculate the mass of Cabr I moles (HBr = 143.45 grams 0.506 mole cubr - grams 0.506 mole cubs x 143.45g cubr I mole cubr - 72.58 grams

② How many grams of 'ch can be produced From ron, Imole ng a 2 mole cel 0.253 mole mg = – cu 0.253 mole ng X a mole cy 1 Mole Ms - 0.506 mole ce produced SO grams ca Imole all a 63.5 0.506 molecer – – ..0.506 mote cu x 63.5 g cu 1 Mole te - 32.13 grams cel