2) Balanced chemical reaction;
Zn + Cu(NO3)2 -----> Cu + Zn(NO3)2
Moles of Cu(NO3)2 = Molarity * volume in liters = 0.1955 * (725/1000) = 0.14174 moles
From balanced reaction;
1 mole Cu(NO3)2 requires 1 mole Zn
So, 0.14174 moles will require = 1 * 0.14174 = 0.14174 moles of Zn
Mass of Zn = moles * molar mass = 0.14174 * 65.38 = 9.27 grams ....Answer
Again from reaction;
1 mole Cu(NO3)2 produces 1 mole Cu
So, 0.14174 mole will produce = 0.14174 moles of Cu
Mass of Cu = moles * molar mass = 0.14174 * 63.5 = 9.00 grams ....Answer
3)
3NO2 + H2O ---> 2HNO3 + NO
moles of NO2 = mass in grams/molar mass = 1.55*1000/46 = 33.696 moles
Moles of water = 0.355 * 1000/18 = 19.72 moles
From reaction;
1 mole H2O requires 3 moles NO2
So, 19.72 mole will require = 3*19.72 = 59.16 moles NO2
However available moles of NO2 = 33.696 which is less than the required one i.e. 59.16
Hence, NO2 is limiting reagent and it will drive the yield of product. And, H2O is excess reagent.
Again from reaction;
3 moles NO2 produces 2 moles HNO3
So, 33.696 mole NO2 will produce = 2*33.696/3 = 22.464 moles HNO3
So, mass of HNO3 produced (theoretical yield) = moles * molar mass = 22.464 * 63 = 1415.23 grams = 1.415 Kg ...Answer
% yield = 0.894 * 100 / 1.41523 = 63.17% ....Answer
Please note that answers may change slightly as molar mass may change slightly. Approach is 100%
Let me know if answer is not matching so that I can review the calculation part.
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