Question

71. The reaction between Copper (II) Chloride and Sodium Nitrate is a simple double replacement reaction. a) Write and balance the reaction between Copper (II) Chloride and Sodium Nitrate b) If 15.0 grams of Copper (II) Chloride react with 20.0 grams of Sodium Nitrate, what is the theoretical yield for Sodium Chloride? A d oi mlbo2 d tal do oA oholdoony2o no d s What is the limiting reagent for this reaction? c) nWnoitulo e chododes sis o bo ei sbixonbH mna8 d) If 11.3 grams of Sodium Chloride are formed during this reaction, what is the percent yield of this reaction? ad s noin to qo tW o

Answer 1

(a)

CuCl₂(aq) + 2 NaNO₃(aq) $\rightarrow$ Cu(NO₃)₂(aq) + 2 NaCl(aq)

(b)

Number of moles of NaNO₃ = 20.0g/84.99g/mol = 0.2353mol

Number of moles of CuCl₂ = 15.0g/134.452g/mol = 0.11156mol

Number of moles of NaNO₃ required to completely react with CuCl₂ = 0.2231mol . Hence the given NaNO₃ present is in excess.

Theoretical yield of NaCl = number of moles of CuCl₂ × 2 = 0.2231mol = 0.2231mol×58.4428g/mol = 13.04 g

Theoretical yield of NaCl = 13.04 g. (Answer)

(c)

Limiting reagent is CuCl₂ .

(d)

% yield of reaction = 11.3g/13.04g × 100% = 86.65 %

= 86.7 %