Question

UCJLIUI. PUMIL D ICU 40.0mL of 0.100M copper(II) chloride solution is reacted with 35.0mL of 0.250M sodium hydroxide solution in the precipitation reaction described in question 1 - part 1. The name of the limiting reagent in this reaction would be and the theoretical yield of A grams (report precipitate would be to 3 significant figures; do not use scientific notation).

Answer 1

1ooo Solutions :- - 10 mL of 0.100 m Copper (11) Chlonids (Cuch] number af mols af luck = no 80.100 number of moles af Cuche = 0.004 mob] - 35 mL of 0.280 m sodiums hydroxide (Nor) = number al mols af Naon = 35% 0-250 = number al mos af Naok=0.00875 mol Reaction is: Cullzog + 2Naong » Cu(OH) 2642 Nails According to "balanud reacters, Imol aml imol Given : 0.004 mol 0.00875 mol ? mol 2000

Limity reagent imol Cuch react with a mol af Nach : 0.004 mol Cucks will react with .008 mol naon but given mol al Naon = 0.00875 Cuck is demiting reagent & Noor is excers reagers Theoretical yield of Ppt (cu Conal - Imol Cuca completely react to produce inch Calen : 0.004 mol Culle will produce = 0.004 mol Culo Molar mass of Culon), = 97.561 g/mol - mars al Cu (oh) = 0.004497-5619 = 0.39029 The name of the limitig reagent in this reactions would be copper (1) chloride and the theoretical gield of Precipitate would be 10.390 g