Question

set - Group! Q1. Consider a parallel-plate capacitor connected to a battery. a) How does the charge in this capacitor change if Potential difference is tripled (by varying the voltage of the battery). (1 mark) b) How the energy does stored change if the capacitance of the capacitor is doubled? Q2. Answer to the following questions by using the above capacitor combination circuit. The values of capacitors are C-18 uF, C2-6 uF C3=36 uF C4-18 uF and Supply voltage, V=72V a) What is the total charge stored in the equivalent capacitor? (2 mark)

Answer 1

Solution) (1) V1 = V

V2 = 3V

Q1 = Q

Q2 = ?

Q = CV

(Q2/Q1) = (V2/V1)

Q2 = Q1(3V/V) = 3Q1

Q2 = 3(Q1)

(b) C1 = C

C2 = 2C

U1 = U

U2 = ?

U = (1/2)(C)(V^2)

U is directly proportional to C

(U2/U1) = (C2/C1)

U2 = (U1)(C2/C1) = (U)(2C/C)

U2 = 2U

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