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8. Calculate the maximum efficiency of an engine which work with a hot source of temperature 2000 and a cold sink of temperature 30 C
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Answer #1

Givens:

Temperature of hot source,200°C, 200 273 473 K

Temperature of cold sink,

T, = 30°C-30+ 273-303 K

The efficiency of the engine is,

  eta=1-rac{T_2}{T_1}​​​​​​

  303 473 = 1-0.64 0.36

  = 36 %

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