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Fall 2019 PChem 7. A certain heat engine operates between 590 °C and 170 °C. (a) What is the maximum efficiency of the engine
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Answer #1

a) Max effieciency = 1 - Temperature of heat sink / temperature of heat source = 1 - 443 / 863 = 0.49 = 49%

The temperatures are in K

b) Efficiency = Work done / heat absorbed

0.49 = 1.0 / Heat

Solving, heat = 2.04 KJ

c) Efficiency = 1 - Heat into cold sink / heat absorbed

0.49 = 1 - 1 / Q

Solving, Q = 1.96 KJ

d)Efficiency = 1 - heat into cold sink / heat absorbed

0.49 = 1 - Q / 1

Q = 0.51 KJ

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