Ans: The FW of alternative C is - $59928
Ans: d ) Alternative C
Explanation:
F = $13000 ( F / P , i , n ) + $450 ( F / A , i , n ) - $1800
= $13000 ( F / P , 15% , 10 ) + $450 ( F / A , 15% , 10 ) - $1800
= $13000 ( 4.0455 ) + $450 ( 20.3037) - $1800
=$52591.5 + $9136.67 - $1800
= $61728.17 - $1800
= - $59928.17
The FW cost of alternative C is less than that of other alternatives. Therefore , alternative C is preferred.
Complete the following analysis of cost alternatives and select the preferred alternative. The study period is...
engineering economy The AW of Alternative A is? The AW of Alternative B is? Two mutually exclusive alternatives are being considered. The MARR is 15% per year. General inflation is 4.5% / year Based on the data below, perform an appropriate analysis to select the most economical alternative. Assume that the market value grows at the general inflation rate. Alternative A Alternative B 51700D5240,000 Initial investment Annual revenue (actual $) $43,000 $48,000 $3,000 in year 1 increasing by $300 each...
Compare alternatives A and B with the present worth method if the MARR is 11% per year. Which one would you recommend? Assume repeatability and a study period of 12 years. $25,000 $10,000 at end of year 1 and increasing by $1,000 per year thereafter None Capital Investment Operating Costs $55,000 $5,000 at end of year 1 and increasing by $500 per year thereafter $5,000 every 3 years 12 years $10,000 if just overhauled Overhaul Costs Life 6 years negligible...
Compare alternatives A and B with the present worth method if the MARR is 10% per year. Which one would you recommend? Assume repeatability and a study period of 20 years $15,000 $45,000 Capital Investment Operating Costs $4,000 at end of year 1 and increasing by $400 per year thereafter $4,000 every 5 years 20 years $8,000 at end of year 1 and increasing by $800 per year thereafter None Overhaul Costs Life 10 years Salvage Value $8,000 if just...
Consider the following EOY cash flows for two mutually exclusive alternatives (one must be chosen). The MARR is 12% per year. Capital Investment Annual expenses Useful life Market value at end of useful life Lead Acid $8,000 $2,250 12 years $0 Lithium lon $13,000 $2,300 18 years $2,800 Click the icon to view the interest and annuity table for discrete compounding when /= 12% per year. (a) Determine which altemative should be selected based on the PW method. Assume repeatabllity...
Consider the following EOY cash flows for two mutually exclusive alternatives (one must be chosen). The MARR is 5% per year. I need the PW of the Lead Acid and Lithium Ion. Problem 6-28 (algorithmic) EQuestion Help Consider the following EOY cash flows for two mutually exclusive alternatives (one must be chosen) The MARR is 5% per year ead Acid $7,000 thium lon Capital investment Annual expenses Useful life Market value at end of useful life $13,000 $2.500 $2,750 12...
Determine the FW of the following engineering project when the MARR is 17% per year. Is the project acceptable? a A negative market value means that there is a net cost to dispose of an asset. Click the icon to view the interest and annuity table for discrete compounding when the MARR is 17% per year. The FW of the following engineering project is $. (Round to the nearest dollar.)
Three mutually exclusive investment alternatives are being considered. The estimated cash flows for each wernative we given below. The study period is 30 years and the firm's MARR is 6% per year. Assume repeatability and reinvestment of positive cash balances at 6 per year a. What is the simple payback period for Alternative 1? b. What is the annual worth of Alternative 2? c. What is the IRR of the incremental cash flows of Alternative 2 compared to Aheative 1?...
For the following table, assume a MARR of 12% per year and a useful life for each alternative of eight years which equals the study period. The rank-order of alternatives from least capital investment to greatest capital investment is Z ·Y? W? X Complete the incremental analysis by selecting the prefer ed altemative. Do nothing" is not an option. $250 $400 $100 Capital investment ? Annual cost savings ? Market value ? PW (12%) 70 100 138 90 50 67...
engineering economy QUESTION 2 The following mutually exclusive investment alternatives have been presented to you A B C E Capital investment $60,000 $90,000 $40,000 $30,000 $70,000 Annual expenses $30,000 $40,000 $25,000 $15,000 $35,000 Annual revenues $50,000 $52,000 $38,000 $28,000 $45,000 MV at EOY 10 $15,000 $15,000 $10,000 $10,000 $15,000 IRR 31.5 % 7.4 % 30.8 % 42.5 % 9.2 % The life span of all alternatives is 10 years.. Using a MARR of 15 % per year, what is the...
Solve for A and B, Engineering Economy please solve it right! Question Help %) Problem 6-52 (algorithmic) Compare alternatives A and B with the present worth method if the MARR is 15% per year. Which one would you recommend? Assume repeatability and a study period of 20 years. $40,000 $7,000 at end of year 1 and increasing by $700 per year thereafter $7,000 every 5 years $15,000 $14,000 at end of year 1 and increasing by $1,400 per year thereafter...