9Given 95% confidence interval for population proportion P is ( 0.27, 0.53)
ie lower limit = 0.27 upper limit = 0.53
then margin of error E = (Upper limit - Lower limit )/ 2
= (0.53- 0.27)/2
E = 0.13
we know lower limit = p-E = 0.27 ..... (1)
Upper limit = p+ E = 0.53 ...... (2)
Substituting E =0.13 IN Equation 1 or 2 , we get p = 0.4
Confidence level = 95%
then Z = 1.96
We know margin of error E = ZSqrt (p( 1-p)/n)
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