22)
Conjugate base is formed after acid looses H+
H2PO4- after loosing H+ forms HPO42-
So, HPO42- is conjugate base
Answer: a
23)
mol of HCl added = 0.089 mol
CN- will react with H+ to form HCN
Before Reaction:
mol of CN- = 0.303 M *1.0 L
mol of CN- = 0.303 mol
mol of HCN = 0.363 M *1.0 L
mol of HCN = 0.363 mol
after reaction,
mol of CN- = mol present initially - mol added
mol of CN- = (0.303 - 0.089) mol
mol of CN- = 0.214 mol
mol of HCN = mol present initially + mol added
mol of HCN = (0.363 + 0.089) mol
mol of HCN = 0.452 mol
Ka = 4*10^-10
pKa = - log (Ka)
= - log(4*10^-10)
= 9.398
since volume is both in numerator and denominator, we can use mol instead of concentration
use:
pH = pKa + log {[conjugate base]/[acid]}
= 9.398+ log {0.214/0.452}
= 9.073
Answer: d
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