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PLEASE HELP TO ANSWER THIS LAB ACTIVITY
Activity 3: Keplers Second Law: Objects in elliptical orbits sweep oul equal areas inequal times. This implies that the orbital speed of a planet around the sun is not uniform - it moves farthest away (known as APHELION). In this section we will calculate the difference in this fastest at the point closest to the sun (known as the PERIHELION) and slowest at the point speed using Pluto as an example. Plutos orbit has an eccentricity e 0.25. Its semi-major axis is 1. Determine the distance (Daphelion) between Pluto and the sun at aphelion. You should be 2. Determine the distance (Dperihelion) between Pluto and the sun at perihelion. Again, you 5.9x10 km, and its mass is 1.47x1022 kg able to determine this using just the semi-major axis and the eccentricity. should be able to determine this using just the semi-major axis and the eccentricity. 3. Keplers Second Law allows us to determine the ratio between Plutos velocity at aphelion and perihelion: Vaphelion/Vperihelion: To do this you need to find the area swept out by Plutos orbit, which can be approximately described as a triangle. Derive an equation for the velocity ratio in terms of the aphelion and perihelion using Keplers Second Law. 4. Plutos minimum orbital velocity is 3.7 km/sec. Determine values for Vaphelion and vperihelion

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