AH = - 1132 kJ 5. Calculate AH for: 4NH3 + 302 → 2N2 + 6H2009...

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Answer 1

Answer #1

no 2NH3(g) + I (22)(8) → 2NO₂ (g) + 3H2O(g) AH=-1132 kJ AK=-27yoly 3 NO2(g) + 4 NH3(g) → 1 Nalg) + 6H, Oly) 6 x reaction 0 +

Answer 2

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