Question

How many grams of solid precipitate is produced if 25.34 mL of 0.113 M BaCl2 is added to an excess of aqueous sodium sulfate?

Hint: First write a balanced equation

Answer 1

Bad, Nasou Basou (s) + 2Nad Basouls) is the precipitute for med moles of Bull, = volume of Ball, in 2'x Helevity of Bally = (25-34x10² L) x (0.113M) Z 0.002 863 43 moles let & be the mass of Bason produced by 0.00286342 molo of Balls. I mol of Bad, gives - 933-38 g of Bason. 0.00286 342 holo of x' Ball, givu Cross multiply X = 0.002863 49 X 333.389 x= 0.6682 6495969.