Balanced chemical equation is:
(NH4)2SO4 + BaCl2 —> BaSO4 + 2 NH4Cl
lets calculate the mol of (NH4)2SO4
volume , V = 10 mL
= 1*10^-2 L
use:
number of mol,
n = Molarity * Volume
= 0.25*1*10^-2
= 2.5*10^-3 mol
According to balanced equation
mol of BaSO4 reacted = (1/1)* moles of (NH4)2SO4
= (1/1)*2.5*10^-3
= 2.5*10^-3 mol
This is number of moles of BaSO4
Molar mass of BaSO4,
MM = 1*MM(Ba) + 1*MM(S) + 4*MM(O)
= 1*137.3 + 1*32.07 + 4*16.0
= 233.37 g/mol
use:
mass of BaSO4,
m = number of mol * molar mass
= 2.5*10^-3 mol * 2.334*10^2 g/mol
= 0.5834 g
Answer: 0.583 g
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