Question

How many mL of 0.250 M BaCl2 would you need to precipitate all the sulfate ion present in 38.1 mL of 0.197 M H2SO4 solution? What is the concentration (M) of the chloride ion remaining in the resulting solution?

Answer 1

first see we balance reaction ,and then see 1 mole of BaCl2 reacts with 1 mole of H2SO4 gives 1 mole of BaSO4 and 2 moles of HCl .

Then first claculte moles of H2SO4 by using molarity and given volume

Molarity = moles / volume (lit)

After this we get moles of H2SO4 ,as we know that 1 mole BaCl2 reacts with 1 mole H2SO4 . So calculated moles of H2So4 reacts with same moles of BaCl2 .

So that now we have moles of BaCl2 and molarity of BaCl2 ,so easily we can calculate volume .