How many grams of magnesium sulfate are needed to make 250.0 mL of a 0.250 M solution? my response was a wrong answer 7.5 grams
0.250M *(250mL* 1L/1000mL)= 0.0625
0.0625* 120.4 g/mol (MgSO4)= 7.525
7.5 grams
Molarity =Number of moles of solute/volume of solution in moles
Therefore, 0.250 M=number of moles of MgSO4/ 0.250 L
Therefore, Number of moles of of MgSO4=0.250 M*0.250 L= 0.0625 Moles of MgSO4
Now, Number of moles of MgSO4 =mass of MgSO4 /molar mass of MgSO4
Therefore, 0.0625 moles= mass of MgSO4 /120.366 (g/mol)
Therefore, mass of MgSO4 =0.0625*120.366 g=7.5229 grams
Thank You!
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