Solution:- Given that n = 411, mean = 30 , standard deviation = 5
a) P(X < 27) = P((X-μ)/( σ/sqrt(n)) <
(27-30)/(5/sqrt(411)))
= P(Z < -12.1638)
= 0
b) P(23 < X < 27) = P((23-30)/(5/sqrt(411)) Z <
(27-30)/(5/sqrt(411)))
= P(-28.3823 < Z < -12.1638)
= 0
c) P(27 < X < 33.3) = P((27-30)/(5/sqrt(411) < Z <
(33.3-30)/(5/sqrt(411)))
= P(-12.1638 < Z < 13.3802)
= 1
d) P(X > 35) = P(Z > (35-30)/(5/sqrt(411)))
= P(Z > 20.2731)
= 0
Problem (15 points) VTE telephone operators are assigned to handle all 411 calls. The mean time...
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