Question

Problem 3-33 (Algorithmic) The time (in minutes) between telephone calls at an insurance claims office has the exponential probability distribution: f(z) 0.40e 0.40s for x 2 0 a. What is the mean time between telephone calls? Mean time (H)- minutes b. what is the probability of 18 seconds or less between telephone calls? (Note: 18 seconds = 0.30 minutes) If required, round your answer to four decimal places. P (x s 0.30)- c. What is the probability of 3 minute or less between telephone calls? If required, round your answer to four decimal places. P(x s 3) - d. What is the probability of 6 or more minutes without a telephone call? If required, round your answer to four decimal places

Answer 1

a. $\mu$ is reciprocal of the constant. which is 1/0.4 = 2.5

b. P(x<=0.3) = 1 - e^-0.3/2.5 = 0.1130

c. P(x<=3) = 1 - e^-3/2.5 = 0.6988

d. P(x<=6) = e^-6/2.5 = 0.0907

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