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Suppose a geyser has a mean time between eruptions of 100 minutes. Let the interval of time between the eruptions be normal d
Suppose a geyser has a mean time between eruptions of 100 minutes. Let the interval of time between the eruptions be normally
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Answer #1

a) P(X > 118)

= P((X - \mu )/\sigma > (118 - \mu )/\sigma)

= P(Z > (118 - 100)/38)

= P(Z > 0.47)

= 1 - P(Z < 0.47)

= 1 - 0.6808

= 0.3192

b) P(\bar x > 118)

= P((\bar x - \mu )/(\sigma/\sqrt n) > (118 - \mu )/(\sigma/\sqrt n))

= P(Z > (118 - 100)/(38/\sqrt 7))

= P(Z > 1.25)

= 1 - P(Z < 1.25)

= 1 - 0.8944

= 0.1056

c) P(\bar x > 118)

= P((\bar x - \mu )/(\sigma/\sqrt n) > (118 - \mu )/(\sigma/\sqrt n))

= P(Z > (118 - 100)/(38/\sqrt {23}))

= P(Z > 2.27)

= 1 - P(Z < 2.27)

= 1 - 0.9884

= 0.0116

d) If the population mean is less than 118 minutes, then the probability that the sample mean of the time eruptions is greater than 118 minutes decreases because the variability in the sample mean increases as the sample size increases.

e) Option - A) The population mean must be more than 100, since the probability is so low.

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