Question

can i please get help with this!!

Suppose a geyser has a mean time between eruptions of 96 mins. let the interval of time between the eruptions be normally distributed with standard deviation 19 mins. complete parts a thru e

(a) What is the probability that a randomly selected time interval between eruptions is longer than 105 minutes? The probability that a randomly selected time interval is longer than 105 minutes is approximately . (Round to four decimal places as needed.) (b) What is the probability that a random sample of 7 time intervals between eruptions has a mean longer than 105 minutes ? The probability that the mean of a random sample of 7 time intervals is more than 105 minutes is approximately (Round to four decimal places as needed) (c) What is the probability that a random sample of 24 time intervals between eruptions has a mean longer than 105 minutes? The probability that the mean of a random sample of 24 time intervals is more than 105 minutes is approximately I (Round to four decimal places as needed.) (d) What effect does increasing the sample size have on the probability? Provide an explanation for this result. Fill in the blanks below on the time hohon an intinns i teater tha

Answer 1

X = time interval between intervals X - Normal (96,19) P(X >105)=P Z> = Pzz 105-96 19 = P(Z > 0.47) = 0.3192 b. P(X >105) = P Z> 105-96 19 = P(Z >1.25) = 0.5-0.3944 0.1056 C. P(X >105) = P Z> 105-96 19 = P(Z > 2.32) = 0.0102

of the population mean is less than 10 minutes, then the probability that the same mean of the time between en is greater than 15 minutes samplesite increases decreases decreases - What might you conclude it a random sample of 24 time intervals between eruptions has a mean longer than 10 minutes Select all that apply A The population mean may be greater than 06 OB. The population mean must be more than , since the probability is so low The population mean cannot be 96, since the probabaty so low D. The population mean may be less than 96 me. The population mean is 96, and this is just a rare sampling DF. The population meanis 95and this is an example of a typical sampling result G. The population mean must be less than 95, since the probability is so low

Z10.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.0 0.0000 0.0040 0.0080 0.0120 0.0160 0.0199 0.0239 0.0279 0.0319 0.10.0398 0.0438 0.0478 0.0517 0.05570.0596 0.0636 0.0675 0.0714 0.20.0793 0.0832 0.0871 0.0910 0.0948 0.0987 0.1026 0.1064 0.1103 0.30.11790.12170.1255 0.1293 0.13310.1368 0.1406 0.1443 0.1480 0.40.15540.15910.1628 0.1664 0.1700 0.1736 0.177210.1808 5.1844 0.5 0.1915 0.1950 0.1985 0.2019 0.2054 0.2088 0.2123 0.2157 0.2190 0.60.2257 0.22910.2324 0.2357 0.2389 0.2422 0.2454 0.2486 0.2517 0.70.2580 0.26110.2642 0.26730.2704 0.2734 0.2764 0.27940.2823 0.80.28810.2910 0.2939 0.2967 0.2995 0.3023 0.3051 0.3078 0.3106 0.90.3159 0.3186 0.32120.3238 0.3264 0.3289 0.3315 0.3340 0.3365 1.0 0.3413 0.3438 0.3461 0.3485 0.3508 0.3531 0.3554 0.3577 0.3599 1.10.3643 0.3665 0.3686 0.3708 0.3729 0.3749 0.3770 0.3790 0.3810 1.2 0.3849 0.3869 0.3888 0.3907 0.3925 0.3944 5.3962 0.3980 0.3997 1.30.4032 0.4049 0.4066 0.4082 0.4099 0.4115 0.4131 0.4147 0.4162 1.40.4192 0.42070.4222 0.4236 0.4251 0.4265 0.4279 0.4292 0.4306

1.70.4554 0.4564 0.45730.4582 0.45910.4599 0.4608 0.4616 0.4625 0.4633 1.8 0.4641 0.4649 0.4656 0.4664 0.46710.4678 0.4686 0.4693 0.4699 0.4706 190.4713 0.47190.4726 0.4732 0.4738 0.4744 0.4750 0.4756 0.4761 0.4767 2.0 0.47720.4778 0.4783 0.4788 0.4793 0.4798 0.4803 0.4808 0.48120.4817 2.10.48210.4826 0.4830 0.4834 0.4838 0.4842 0.4846 0.4850 0.4854 0.4857 2.2 0.4861 0.4864 0.4868 0.4871 0.4875 0.4878 0.4881 0.4884 0.4887 0.4890 2.30.4893 0.4896 0.4898 D.4901 0.4904 0.4906 0.4909 0.4911 0.4913 0.4916 2.40.4918 0.4920 0.4922 0.4925 0.4927 0.4929 0.4931 0.4932 0.4934 0.4936 2.5 0.4938 0.4940 0.4941 0.4943 0.4945 0.4946 0.4948 0.4949 0.49510.4952 2.6 0.4953 0.4955 0.4956 0.4957 0.4959 0.4960 0.4961 0.4962 0.4963 0.4964 2.70.4965 0.4966 0.4967 0.4968 0.4969 0.4970 0.49710.4972 0.4973 0.4974

X = time interval between intervals X - Normal (96,19) P(X >105)=P Z> = Pzz 105-96 19 = P(Z > 0.47) = 0.3192 b. P(X >105) = P Z> 105-96 19 = P(Z >1.25) = 0.5-0.3944 0.1056 C. P(X >105) = P Z> 105-96 19 = P(Z > 2.32) = 0.0102

of the population mean is less than 10 minutes, then the probability that the same mean of the time between en is greater than 15 minutes samplesite increases decreases decreases - What might you conclude it a random sample of 24 time intervals between eruptions has a mean longer than 10 minutes Select all that apply A The population mean may be greater than 06 OB. The population mean must be more than , since the probability is so low The population mean cannot be 96, since the probabaty so low D. The population mean may be less than 96 me. The population mean is 96, and this is just a rare sampling DF. The population meanis 95and this is an example of a typical sampling result G. The population mean must be less than 95, since the probability is so low