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A sample of n = 10 automobiles was selected, and each was subjected to a 5-mph crash test. Denoting a car with no visible damage by S (for success) and a car with such damage by F, results were as follows: S S F S S S S F S S (a) What is the value of the sample proportion of successes x/n? (b) Replace each S with a 1 and each F with a o. Then calculate x for this numerically coded sample. How does x compare with x/n? The proportion in part (a) is exactly equal to the mean in part (b) The proportion in part (a) is greater than the mean in part (b). The proportion in part (a) is less than the mean in part (b) (c) Suppose it is decided to include 15 more cars in the experiment. How many of these would have to be Ss to give x/n0.56 for the entire sample of 25 cars? cars Need Help? Talk to sTutor Read It

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Answer #1

Answer: ---- Date: ----31/01/2019

The data is denoting about the no visible damage (S) and damage (F) There are 8 cars with no visible damage. Number of success 8 Sample size 10 The sample proportion of successes of cars having no visible damage is, n 10 -0.8 Thus, the sample proportion of successes is 0.8

Replace each S with 1 and F with 0. Then, 1 10 1 1 1 1 0 11 Now, the mean of the coded sample is, Mean,- = 10 10 =0.8

Thus, the mean of the coded sample is 0.8. If more 15 cars are included and the total number of cars is 25, then the number of cars should be S to get0.56 is calculated as follows: The number of successes is x = 0.56 x 25-14 Since 8cars with are there in sample of 10, so 14 8-6 cars with S are required to get the proportion of success as 0.56

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