5. An Olympic high diver is launching off the diving board at a height of 2...

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Answer 1

Answer #1

a) Ug = m*g*h

= 85*9.8*2

= 1666 J

b) U_spring = (1/2)*k*x^2

= (1/2)*170*0.5^2

= 21.25 J

c) kinetic energy of the swimmer when he enters the water = Ug + U_spring

KE = 1666 + 21.35

KE = 1687.35 J

now use, KE = (1/2)*m*v^2

==> v = sqrt(2*KE/m)

= sqrt(2*1687.35/85)

= 6.30 m/s

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Answer 2

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