Question

For the following reaction, 6.90 grams of sulfuric acid are mixed with excess calcium hydroxide, The reaction yields 6.76 grams of calcium sulfate. sulfuric acid (aq) + calcium hydroxide (s) - calcium sulfate (S) + water (1) What is the theoretical yield of calcium sulfate? grams What is the percent yield for this reaction?

Answer 1

Ans:- Given that H2SO4 (aq) + Calon), (s) - casou (s) + 2H2641) I mole of H₂SO4 produces a mole of casoy mass of H₂SO4 = 6.909 molar mass of H₂SO4 = 98.079 g/mol moles = mass molar mass 6.90 g 98.079 g/mol moles - 0.0703 0.0703 molesof Hasou should produce 0.6703 moles of casou moles o casoy = 0.0703 moles mass = moles y molar mass molar mass do casoy = 136. 14 g/mol mass = 0.0703 mol x 136.14 gimol - 9.577 g (Theoritical yield) sulphate Theoritical tical yield of calcuium - 91577 gram Actual yield yield to 1.5 gram afo yield - 100 % Theoretical vied *

6.76 gram ( given) * 100 9.577 gram = 0.705 x 100 7. yiel = 70585