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(References . An aqueous solution contains 4.60 g of calcium chloride, CaCl, per liter. What is the molarity of CaCl? Molarit
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Answer #1

a)

Molar mass of CaCl2,

MM = 1*MM(Ca) + 2*MM(Cl)

= 1*40.08 + 2*35.45

= 110.98 g/mol

mass(CaCl2)= 4.60 g

use:

number of mol of CaCl2,

n = mass of CaCl2/molar mass of CaCl2

=(4.6 g)/(1.11*10^2 g/mol)

= 4.145*10^-2 mol

volume , V = 1 L

use:

Molarity,

M = number of mol / volume in L

= 4.145*10^-2/1

= 4.145*10^-2 M

Answer: 4.14*10^-2 M

b)

[Ca2+] = [CaCl2]

= 4.14*10^-2 M

Answer: 4.14*10^-2 M

[Cl-] = 2*[CaCl2]

= 2*4.14*10^-2 M

= 8.28*10^-2 M

Answer: 8.28*10^-2 M

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