Question

References A 2.00 g sample of KCI is dissolved in 65.0 mL. of water. The resulting solution is then added to 15.0 mL. of a 0.430 M CaCl, (aq) solution. Assuming that the volumes are additive, calculate the concentrations of each ion present in the final solution. Concentration of K ions M Concentration of Ca ions Concentration of CI ions M Submit Answer Try Another Version 6 item attempts remaining

Answer 1

AnEwer mas ot K CJ in olut: on moles o KCI preren Mokar ma s o1 kul 2.00 74. 5513mo D. 026P2169 moj Moles o Ca Cl pner entn soluti) Moloyty C U2 Ca C Volume o Is. ο mL o.430M moY s.oxlo-3 L_ O.430 0.00 64S mo Volume t Solu ton additve so Now Volues are 65.0m 15. o mL 80. o mL 80.0 x0-3 L NoD Anamalartties in Solut!on molej ot kCi (kc= 0.0 26827 16y no Volqme O00 L 0.3353395s M

C.q5xo-3m0) ৫१८,) = o.Dgo L o. o 8 O62-5 Ea cl Lompletely i ur Ke ana Nouo IM CI К* M qnd five KCI Kt IM Ca 2 M CI qne Ca 2t 2 kc o. 33 533 9 55 M giv e o. 33 5 33 9S s M k+ qnd 0.33 53 3 955 M o.080625M :ves Ca 2 2X o.o806 25 M CIT Total C 0.33 5 33 9 55)+ (2x 0-080625) ^g [C3 o.49658955 M [K1) .33 5339SS M 0.08o 615 0.3353M 0.080C M cr 0496C M