![The free energy change for the following reaction at 25 °C, when [Pb2+] = 1.18 M and [Cd2+] = 1.44*10-3 M, is -70.1 kJ: Pb2+(](http://img.homeworklib.com/questions/53f10880-70b6-11ea-9d75-1db6d5ce1f49.png?x-oss-process=image/resize,w_560)
Homework Answers
1) DG = -nFEcell
DG = 70.1 kj
n = no of electrons transfered = 2
F = faraday = 96500 c
Ecell = cell potential = ?
70.1*10^3 = -2*96500*x
x = Ecell = -0.363 V
answer: Ecell = -0.363 V
as DG is +ve for the forward reaction. so that, it is non spontaneous.where as the backward reaction is spontaneous.
answer: spontaneous in reverse direction.
2) DG = -nFEcell
DG = - 70.1 kj
n = no of electrons transfered = 2
F = faraday = 96500 c
Ecell = cell potential = ?
- 70.1*10^3 = -2*96500*x
x = Ecell = 0.363 V
answer: Ecell = 0.363 V
as DG is -ve for the forward reaction.so that, it is spontaneous.
answer: spontaneous in forward direction.
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