Question

Constants PartA Coulomb's law for the magnitude of the force F between two particles with charges Q and What is the net force exerted by these two charges on a third charge 530 nC placed between gh and g Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures separated by a distance d is at1.060 m? IFI-Klod! where K space 4L and 60-8854 × 10 i2 C)/(N-m2) is the permittivity of free View Available Hint(s) Consider two point charges located on the x axis one charge. g -19.0 nC is located at z1--1 555 m ; the second charge, g2-30.0 nC . is at the origin (z = 0.0000) orce on g- Submit Provide Feedback

Answer 1

As we know that +q and +q repel each other , +q and -q attract each other then just use this concept as :-

According to coulomb's law: - F = 1/4 pi epsilon_0 q_1 q_2/r^2 N F = K q_1 q_2/r^2 then the force on q_3 due to the charge q_2: - F_q_2 = k(53 times 10^- 9 c) (30 times 10^- 9 c)/1.060 m)^2 F_q_2 = 9 times 10^9 times 53 times 10^- 9 times 30 times 10^- 9/1.1236 F_q_2 = 14310/1.1236 times 10^- 9 = 127.36.85 times 10^- 9 N (- i) again the force on Q_3 due to the chare q_1: - F_q_1 = k (53 times 10^- 9 c) times (19 times 10^- 9)c/(0.595 m)^2 F_q_1 = 9 times 10^9 times 53 times 10^- 9 times 19 times 10^- 9/0.3540 F_q_1 = 9063/0.3540 times 10^- 9 = 25601.69 times 10^- 9 N(- i) \r\n then the resultant force or Net force: - F_net = F_q_1 + F_q_2 = 25601.69 times 10^- 9 (- i) + 12735.85 times 10^- 9 (- i)

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