Solution
1.
Information given,
Investment (P) = $5000
Rate of Interest (r) = 6%, or 0.06
(a)
If, Term of Deposit (n) = 10 Years
and, Number of Compounding, if Monthly (m)= 12
Therefore,
Effective Annual interest rate = (1 + r/m)m - 1
Or, (1 + 0.06/12)12 - 1
Or, (1 + 0.005)12 - 1
Or, (1.005)12 - 1
Or, 1.0617 - 1 [(1.005)12 = 1.0617 (Approx.)]
Or, 6.17%
Therefore, the Effective Annual interest rate will be 6.17%.
(b)
Now, the balance will be after 10 years will be calculated as
follows (given that amount compounds monthly)
Investment (P) = $5000
Effective rate (R) = 6.17%
Term (n) = 10
So, balance after 10 years will be,
Future Value (F) = P x (1 + R)n
Or, 5000 x (1 + 0.0617)10
Or, 5000 x 1.8198 [(1 + 0.0617)10 = 1.8198
(Approx.)]
Or, 9099
Therefore, the amount will be $9099
(c) Now, if compounding weekly, then Effective rate will
be,
(1 + r/m)m - 1 (As compounding weekly, number of
compounding (m) = 52)
Or, (1 + 0.06/52)52 - 1
Or, (1 + 0.0012)52 - 1
Or, 1.0643 - 1 [(1 + 0.0012)52 = 1.0643 (Approx.)]
Or, 6.43%
Now, using this rate, the future value will be = 5000 x
(1.0643)10
Or, 5000 x 1.8648 [(1.0643)10 = 1.8648 (Approx.)]
Or, 9324
Therefore, if compounding done weekly, balance should be increased by $(9324 - 9099) = $225
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