Question

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10. An amine is typically a poor leaving group. An amine can be converted to a good leaving group when treated with excess methyl iodide. The iodide salt is converted to the hydroxide salt using silver oxide and upon heating an E2 reaction occurs. This synthetic sequence is usually referred to as the Hofmann elimination. The reaction commonly favors the formation of the least substituted alkene. excess CH 31 R-N(CH), 1 Ag,0 - — R-N(CH.), OH alkene – R-NH2 + N(CH) + H2O 2 HI AgI 1. excess CH, + N(CH), + H2O 11. Ag,0 Predict the product for the following Hofmann elimination: 0 i CHI ii Ag 0.H.O 111. heat 0.4.0 ? (CH,

Answer 1

Som.. 11) A820, H₂O UCM2 I ON Jo act as stone CH3 base СИ. I + H₂O Product @ (monosubstituted)