 Rate (mol-1,-1) 0.0450 162 * 10-3 0.0310 7.69 x 10-4 0.0095 7.22 x 10-5 B](http://img.homeworklib.com/questions/3af54130-70c4-11ea-a939-e545f70b50b7.png?x-oss-process=image/resize,w_560)
Homework Answers
Let the rate law be:
Rate = k [NOBr]^x
From row 1:
Rate = k [NOBr]^x
1.62*10^-3 = k (0.0450)^x
From row 2:
Rate = k [NOBr]^x
7.69*10^-4 = k (0.0310)^x
Divide 1st equation by 2nd one
1.62*10^-3 / 7.69*10^-4 = (0.0450/0.0310)^x
2.11 = (1.45)^x
(1.45)^2 = (1.45)^x
So,
x = 2
The rate law is:
Rate = k [NOBr]^2
Put values from row 1
1.62*10^-3 mol.L-1.s-1= k (0.0450 mol.L-1)^2
K = 0.800 L.mol-1.s-1
Answer: b
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