FeCo alloy thin film is a fundmental material for the STT-MRAM. It is a FCC structure when disordered and L10 structure when 100% ordered. For the perpendicular magnetic anisotropy, L10 structure with FeCo(100) perpendicular to the surface is preferred. I prepare the thin film by magnetron sputtering. Suppose I should prepare the FeCo alloy with atomic ratio of 1:1 in an ideal case. However, due to poor preparation of co-sputtering, the atom is 5:3 (iron rich FeCo thin film), the structure of Fe rich thin film is noy known. Anonalous X-ray scattering was perform to solve this issue. Three kind of models is proposed. In the first model, the addition Fe is segregated form the order FeCo (1:1) L10 structure, and fill in the grain boundaries. The second model is totally disorder FCC structure (order parameter is zero) and addition Fe is dissolved into a solution. The third model is Fe atom replaces 1/4 part of Co atom positions in the L10 structure.
(a) Please calculate the diffraction intensity ratio of
FeCo(001)/FeCo(002) for these three models using 12 KeV X-rays. To
simplify the question, we assume the atiomic structure factor is
constant (usually, atomic structure factor is a function of q)
, . In addition,
all the FeCo alloys are in cubic structure and the lattice
constants are all the same from 0-100% ordering
(b) In order to gain the sensitivity of determining the order parameter, I charge the energy of X-ray form 12 KeV to the K-edge of Fe (7.112 KeV). The atomic structure factor of Fe is changed by adding the dispersive factor of , which is around 5. Please also calculate the X-ray diffraction intensity ratios of FeCo(001)/FeCo(002) of the FeCo alloy for these three models, Hint: and this method called anomalous X-ray scattering method.
(Please, answer All two question please , the type format is the best)
1. For a diffraction intensity the intensity is directly proportional to the structure factor ( F )
I F2
so calculating different value of structure factors for all three models.
1 . for 1st model
F = f( FeCo) ei [ 2 ( hx + ky + lz ]
also f( FeCo) = fFe + fCo = 26+27 = 53
so F for FeCo ( 001 ) is
F = 53 ei [ 2 ( h(0) + k(0) + l(1)] = 53 ei [ 2( l )] ( h+k+l = odd ) so BCC
for FeCo ( 002 )
F = 53 ei [ 2 ( h(0) + k( 0) +l (2)] = F = 53 ei 2(2l)
2. for 2nd model ( FCC )
the structure value is given as F = f ( 1+ei ( h+k) + ei( k+ l )+ ei( l + h )
for FeCo ( 001) F = 53 ( 1+ ei(h + k)(0)+ ei(k+l)(0)+ei(l + h)(1)
similarly find out for FeCo ( 002) coordinate
3. for third model the Fe atom is replaced by 1/4 th of Co atoms
so fFe = 1/4 x 27 =6.75 so fFeCo = 6.75 + 27 = 33.75
Now the structure value of F can be calculated as the 1st model just by putting the value of fFeCo = 33.75
2. as the value of f' = 5 so,
FeCo alloy thin film is a fundmental material for the STT-MRAM. It is a FCC structure...
10. The metal iridium has an FCC crystal structure. If the angle of diffraction for the (220) set of planes occurs at 69.22° (first-order reflection) when monochromatic x-radiation having a wavelength of 0.1542 nm is used, compute (a) the interplanar spacing for this set of planes and (b) the atomic radius for an iridium atom.