Question

Part E List the number of each type of atom on the right side of the equation C2H6(9) + 7 O2(g) + 3 CO2(g) + 6H2O(9) Enter your answers separated by commas (the order of the numbers is the same as the order of the elements on the left side of the equation).

Answer 1

The given equation is

C2H6(g) + 702(g) + 3C02(g) + 6H209

We have to list the number of each type of atom present in the right side of the equation.

Also, we have to list them in the order C, H and O as they appear on the left side.

On the right side, only one of the molecules contains carbons i.e. CO2.

Since each CO2 contains 1 carbon atom and there are 3 CO2 on the right side, the number of C atoms on the right is 3.

Only one molecule on the right contains H atoms i.e. H2O.

Since there are 6 H2O and each H2O contains 2 H atoms, the number of H atoms on the right side is .

2 x 6 = 12

Both the molecules on the right side contains O atoms.

Each CO2 contains 2 O atoms. Hence, the number of O atoms from 3 CO2 = .

3 x 2 = 6

Each H2O contains 1 O atom. Hence, the number of O atom from 6H2O =

6x1= 6.

Hence, the total number of O atoms on the right side = 6 + 6 = 12.

Hence, your answer for the number of C, H and O atoms will be

3. 12.12