ZuoTi.Pro
Question

The length of time it takes to complete a word puzzle is found to be normally...

The length of time it takes to complete a word puzzle is found to be normally distributed with a mean of 76 seconds and a standard deviation of 8 seconds. Using the ​50% dash –​34% dash –​14% ​figures, find the approximate percentages of scores​ (on time to complete the word​ puzzle) that will be above or below the following values. ​(a) Above 76 ​(b) Below 76 ​(c) Above 60 ​(d) Below 60 ​(e) Above 84 ​(f) Below 84 ​(g) Above 68 ​(h) Below 68 ​(i) Above 92 ​(j) Below 92

math   Statistics-And-Probability   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

ED B.luhion I=76 2.51 2 5 IAsing Embincal ules 7 Abore Abore 76 / So b) Bolow 6 : Belous e So Abou (76-2x) S Abou u- c) Abore

0 0
Add a comment
Know the answer?
Add Answer to:
The length of time it takes to complete a word puzzle is found to be normally...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • The length of time it takes to complete a word puzzle is found to be normally...

    The length of time it takes to complete a word puzzle is found to be normally distributed with a mean of 70 seconds and a standard deviation of 10 seconds. Using the ​50% dash –​34% dash –​14% ​figures, find the longest time to complete the word puzzle that a person can have while being in the bottom most percentages of scores for each of the following percentages. ​(a) 84​% ​(b) 16​% ​(c) 2​% ​(d) 98​% ​(e) 50​%

  • 3. The amount of time it takes to complete a task is normally distributed with a...

    3. The amount of time it takes to complete a task is normally distributed with a mean of 34 minutes and a standard deviation of 4 minutes. If I take a sample of 24 people how many of those 24 people on average will take over 37 minutes to do the task?

  • 8. (8 pts) The length of time for students to complete a test is found to...

    8. (8 pts) The length of time for students to complete a test is found to be normally distributed with mean 70 minutes and standard deviation 12 minutes. How long should the time for the test be if we wish for 90 percent of the students to complete the test in less time than the test length? (Use the Normal table provided for your calculations)

  • A set of 1100 exam scores is normally distributed with a mean = 84 and standard...

    A set of 1100 exam scores is normally distributed with a mean = 84 and standard deviation = 4. Use the Empirical Rule to complete the statements below. How many students scored higher than 84? How many students scored between 80 and 88? How many students scored between 76 and 92? How many students scored between 84 and 88? How many students scored lower than 80? How many students scored lower than 88?

  • The length of time needed to complete a certain test is normally distributed with mean 23...

    The length of time needed to complete a certain test is normally distributed with mean 23 minutes and standard deviation 11 minutes. Find the probability that it will take more than 20 minutes to complete the test.

  • The time it takes students to complete an ES1-3215 final exam is normally distributed with a...

    The time it takes students to complete an ES1-3215 final exam is normally distributed with a mean of 73 min and a standard deviation of 21 min. How much time should be allowed to ensure that 90.0% of the students can complete the exam on time? (Round numerical value to the nearest minute) 98 min 103 min 100 min None of the given numerical values is correct 109 min Not enough information to answer the question 112 min 96 min

  • assume that the number of days it takes a homebuilder to complete a house is normally...

    assume that the number of days it takes a homebuilder to complete a house is normally distributed with an average completion time of 176.7 days and a standard deviation of 24.8 days. Determine the completion time that the builder has a 40% probabilty of acheiving.

  • The time it takes students to complete an ES1-3215 final exam is normally distributed with a...

    The time it takes students to complete an ES1-3215 final exam is normally distributed with a mean of 74 min and a standard deviation of 21 min. How much time should be allowed to ensure that 90.0% of the students can complete the exam on time? (Round numerical value to the nearest minute) Not enough information to answer the question 95 min O 101 min 97 min 99 min 112 min O None of the given numerical values is correct...

  • The time it takes a randomly selected rat to complete a maze is normally distributed with...

    The time it takes a randomly selected rat to complete a maze is normally distributed with mean 1.5 minutes and standard deviation 0.35 minutes. (a) Find the probability that a randomly selected rat spends longer than 1.6 minutes to complete it. (b) We randomly take a sample of 100 rats. Find the probability that the average completion time for the sampled rats is smaller than 1.6 minutes. (c) We randomly take a sample of 4 rats. Find the probability that...

  • The time it takes students to complete an ESI-3215 final exam is normally distributed with a...

    The time it takes students to complete an ESI-3215 final exam is normally distributed with a mean of 70 min and a standard deviation of 20 min. How much time should be allowed to ensure that 95.0% of the students can complete the exam on time? (Round numerical value to the nearest minute) O 103 min 101 min O 110 min O 106 min Not enough information to answer the question O None of the given numerical values is correct...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT