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Exercise 1.23. Compute the probability that a bridge hand (13 cards chosen at ran- dom from an ordinary deck of 52 cards) is void in at least one suit.
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TOPIC: Use of the Classical definition of probability.

Exena se we kwaw, among the 5 cands o an andnar dea, 13 cands can be se leated n 52. 13 ways, which aa mutually exclusive exhaustive and equally ayine, the dollowing events a v, 2 The bridge hand i vad in exacty ơne suit, 2 su ana theezsw To dind f(v) the bodge hand as void in exa one cuitj: then, it must contain 13 cards drom tne otnen three suits. Now,ǐjvosuit out of 4 suits ean be Aelac ted n 4w and among the (3 x 1 39 cartds of trat three suits, 13 catd can be pe les ted in 33 )wayo. So, tne total mo ways celesting a bwidge hand, (whene exae ona suit is void) is x39 L3 391 x 52.To dind, P (V) ated(1 13 x2) 26 cords theu two sua Cards can be drawn in 26) 2) W ts, and from the total here, we get 2.6 52 13 To dind, r(%) : Here exactiy three Awts void 3 duts can he chosenna, and 30 13 cam the romain in ome suit, 13 cards can be seleeted n 13 13 .S1mǐ 52 13ence, Ye 521 13 3 9 1 3 31し13

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