In a test of H0:μ = 100 against Ha:μ ≠ 100, the sample data yielded the test statistic z = 2.30. Find the P-value for the test.
P = _______
In a test of H0:μ = 100 against Ha:μ ≠ 100, the sample data yielded the test statistic z = 2.30
In a test of H0:μ = 100 against Ha:μ ≠ 100, the sample data yielded the test statistic z = 2.07. Find the P-value for the test. P= (Round to four decimal places as needed.)
B. H0:μ=12 vs. HA:μ<12H0:μ=12 vs. HA:μ<12 C. H0:μ=12 vs. HA:μ>12H0:μ=12 vs. HA:μ>12 D. H0:μ=12 vs. HA:μ≠12H0:μ=12 vs. HA:μ≠12 2. Which conditions must be met for the hypothesis test to be valid? Check all that apply. A. The observations are independent B. There must be at least 3 levels of the categorical variable. C. Population data must be nearly normal or the sample size must be at least 30. D. There must be an expected count of at least 5 in...
You need to test H0: μ=10 against H1: μ>10. The test statistic was found to be, Ztest=1.72. The P value of the test should be: 0.0427 0.9573 0.0854 You need to test H0: μ=100 against H1: μ<100. The P value of the test was found to be 0.0001. A possible 95% confidence interval is: -∞, 99.5 -∞, 78.6 110.3, ∞ A 95% upper confidence interval for the tensile strength of 0.05 millimeter (mm) Sisal fiber in Megapascals...
The t statistic for a test of H0:μ=10 HA:μ<10 based on n = 10 observations has the value t = -2.15. (a) What are the degrees of freedom for this statistic? (b) Using the appropriate table in your formula packet, bound the p-value as closely as possible: < p-value <
In testing H0:μ=77 versus Ha:μ≠77 for some population, a random sample of 17 observations from a normally distributed population with unknown standard deviation yielded a test statistic of 2.638. The p-value for this test is Select one: a. 0.0041 b. between 0.005 and 0.010 c. between 0.01 and 0.02 d. 0.0082 e. impossible to determine based on the given information.
Assume that z is the test statistic. (a) H0: μ = 22.5, Ha: μ > 22.5; x = 25.8, σ = 6.2, n = 36 (i) Calculate the test statistic z. (Round your answer to two decimal places.) (ii) Calculate the p-value. (Round your answer to four decimal places.) (b) H0: μ = 200, Ha: μ < 200; x = 191.1, σ = 33, n = 27 (i) Calculate the test statistic z. (Round your answer to two decimal places.)...
Assume that z is the test statistic. (a) H0: μ = 22.5, Ha: μ > 22.5; x = 25.9, σ = 7.4, n = 33 (i) Calculate the test statistic z. (Round your answer to two decimal places.) (ii) Calculate the p-value. (Round your answer to four decimal places.) (b) H0: μ = 200, Ha: μ < 200; x = 193.8, σ = 35, n = 36 (i) Calculate the test statistic z. (Round your answer to two decimal places.)...
ssume that z is the test statistic. (a) H0: μ = 22.5, Ha: μ > 22.5; x = 24.8, σ = 7.3, n = 37 (i) Calculate the test statistic z. (Round your answer to two decimal places.) (ii) Calculate the p-value. (Round your answer to four decimal places.) (b) H0: μ = 200, Ha: μ < 200; x = 192.1, σ = 34, n = 32 (i) Calculate the test statistic z. (Round your answer to two decimal places.)...
Assume that z is the test statistic. (a) H0: μ = 22.5, Ha: μ > 22.5; x = 26.7, σ = 7.4, n = 21 (i) Calculate the test statistic z. (Round your answer to two decimal places.) (ii) Calculate the p-value. (Round your answer to four decimal places.) (b) H0: μ = 200, Ha: μ < 200; x = 192, σ = 35, n = 20 (i) Calculate the test statistic z. (Round your answer to two decimal places.)...
In testing H0: μ = 10 vs Ha: μ 6= 10, we find the test z-statistic is z(obs) = −2.5 Find the P-value of the test.