At first I have given the natural case so that u will understand the theory first !!.. then I have focused on special cases:-
2. The rotation of the earth might have an effect on g measured on the Earth....
Task 2 (Gravitational Potential of the Earth) In good approximation, the earth can be regarded as a sphere of homogenous mass density with radius R and total mass M. The gravitational potential of a mass m which has a distance r to the center of the earth is given by GMm , r>R U(r) 2R where Eo and G are constants a) Calculate the force F(r) which acts on a mass m at the earth's surface Hint: The gradient of...
Can someone explain the equation: g'=g-omega^2r This equation is for this question, but I need to know how to get to this equation. Estimate the effect of Earth's rotation (centripetal acceleration) on the gravitational acceleration at: The Equator North Pole Baton Rouge, LA (The latitude is about 30
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2) towards the Earth's axis of a person standing on the surface of the Earth at a latitude of 62.2∘? Recall that latitude is measured from the equator, and assume the Earth's radius is 6,370 km.
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2g=9.8 m/s2) towards the Earth's axis of a person standing on the surface of the Earth at a latitude of 78.9∘78.9∘? Recall that latitude is measured from the equator, and assume the Earth's radius is 6,370 km6,370 km.
Earth Mass/Radius: 1 M= 5.97 x 10^24 kg 1 R= 6.38 x 10^6 m Compare th centripetal force of s 75 kg person standing on the equator of the earth to that of the gravitational force due to the earths rotation. In other words, compute the ratio ( F gravitational/ F centripetal). How many revolutions per day would the earth have to turn to make these forces equal to one another (to makes this ratio exactly 1)?
So far in your life, you may have assumed that as you are sitting in your chair right now, you are not accelerating. However, this picture is not quite complete! You are on the surface of the Earth, which is rotating. 1. a) What is the acceleration of a person sitting in a chair on the equator? b) The latitude of Corvallis is 44.4". What is your acceleration while sitting in your chair? (c) Is your apparent weight greater than,...
Does the force of gravity alone provide the means for the centripetal force, is this why they are equal ? For explaining why there is no normal force, could you see it as the astronaut having the same acceleration as the ship and so the relative acceleration = 0, so it's under the illusion almost of having no acceleration so there's no force ? Please !! If you have different reasoning please share. I'm just trying to wrap my head...
1. (constancy of "g") First, we ignore rotation. According to the law of gravitation the force per unit mass on an object above Earth's surface has amplitude GM/r2, wherer is the distance from the object to the center of Earth, G is the gravitational constant and M is the mass of the earth. For a point in the atmosphere at elevation z above the surface, we can write r = 2 + a where a is the radius of a...
QUIZE LAB 8 GRAVITY AND AIR RESISTANCE a. Select the true statement(s): (2 points) In vacuum, all objects, no matter the mass, should theoretically fall with the same acceleration The weight of an object on Earth is same as the weight it would have on the moon. The weight would vary slightly at different locations on the earth's surface becauseg varies slightly from place to place on the earth. * * . The gravitational acceleration g 4.9 N/k 2. Select...
tonHint: The assumption was not "it's moving in a circle."1 2. Claiming that a particle is moving in a circle with a constant radius is logically/mathematically equiv- 3. Consider a particle moving in a cirele of radius R. How is it posible for the particle to experience an 4. After deriving the formula for centripetal acceleration, we were inspired by Newton's d Law to alent to two other claims. State at least one of those claims. acceleration when its speed...