What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2g=9.8 m/s2) towards...
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2g=9.8 m/s2) towards the Earth's axis of a person standing on the surface of the Earth at a latitude of 78.9∘78.9∘? Recall that latitude is measured from the equator, and assume the Earth's radius is 6,370 km6,370 km.
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What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2g=9.8 m/s2) towards...
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2) towards the...
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2) towards the Earth's axis of a person standing on the surface of the Earth at a latitude of 62.2∘? Recall that latitude is measured from the equator, and assume the Earth's radius is 6,370 km.
a. Compute the centripetal acceleration of a point on the surface of the Earth at the...
a. Compute the centripetal acceleration of a point on the surface of the Earth at the equator caused by the rotation of the Earth about its axis. Enter the magnitude. The radius of the Earth is 6,371 km. The period is one day. m/s2 b. Suppose the Earth were spinning much faster. Find the period that results in the centipetal acceleration being equal to 9.8 m/s?. minutes When the centripetal acceleration equals the acceleration due to gravity, objects are in...
We found the centripetal acceleration of the Earth as it revolves around the Sun. Compute the...
We found the centripetal acceleration of the Earth as it revolves around the Sun. Compute the centripetal acceleration of a point on the surface of the Earth at the equator caused by the rotation of the Earth about its axis. (Enter the magnitude. The radius of the Earth is 6,371 km.) m/s2
A rocket travels horizontally, close to the earth. The centripetal acceleration of the rocket is the...
A rocket travels horizontally, close to the earth. The centripetal acceleration of the rocket is the earth's gravity (9.8 m/s2). If the earth's radius is 6.3 x 106 m and we neglect air resistance, how fast must the rocket be going to keep a constant height above the earth's surface?
(25 pts) Make a plot of the gravitational magnitude acceleration versus radius for a satellite in...
(25 pts) Make a plot of the gravitational magnitude acceleration versus radius for a satellite in Earth orbit. The x-axis should be the orbital radius in units of Earth radii, from Earth's surface, 6,378 km, to 75,000 km. The y-axis should be the computed acceleration in units of m/s2. Be sure to label your plot.
+ -/1 points 0/1 Submissions Used What is the centripetal acceleration of the Earth for a...
+ -/1 points 0/1 Submissions Used What is the centripetal acceleration of the Earth for a person standing 5600000 m from the axis? The period of rotation of the earth is one day or 86400 seconds centripetal acceleration Does your answer make sense from what you know about standing on the Earth? Should it be a large acceleration or a small acceleration? m/sA2
Calculate the magnitude of your centripetal acceleration due to Earth’s rotation on its axis (standing on...
Calculate the magnitude of your centripetal acceleration due to Earth’s rotation on its axis (standing on the ground here in LA). Why doesn’t this rotation send you flying off the surface of the Earth?
Earth's radius is 638 x 10^6 m, and it completes one revolution every day. What is...
Earth's radius is 638 x 10^6 m, and it completes one revolution every day. What is the magnitude of the centripetal acceleration of a person standing on the equator?A) 0.00844 m/s^2 B) 0.00343 m/s^2 C) 0.0337 m/s^2 D) 0.343 m/s^2 E) 0.000854 m/s^2
The earth (of radius of 6371km) rotates on itself at a rate of one revolution every 24 hours and is titled by an angle of 23.5°. Let's assume that the earth is a perfect sphere, which allows us t...
The earth (of radius of 6371km) rotates on itself at a rate of one revolution every 24 hours and is titled by an angle of 23.5°. Let's assume that the earth is a perfect sphere, which allows us to consider a uniform circular motion 23.5 R equator Figure 1: Earth rotation Everybody on earth share the same time of rotation, but based on their location on the earth, they wil have different velocities. A person located in Hawaii, at an...
A body is in an elliptical orbit about the earth. The magnitude of the acceleration of this body ...
A body is in an elliptical orbit about the earth. The magnitude
of the acceleration of this body is g (Re/R)^2, where R is the
distance from the body to the center of the earth, Re = 6,370 km,
and g = 9.807 m/s^2 . At the position shown, the speed of the body
is 27,000 km/hr. Determine the rate of change of the speed and the
radius of curvature of the orbit at this position.
9,000 km 12,000 km...
a. Compute the centripetal acceleration of a point on the surface of the Earth at the equator caused by the rotation of the Earth about its axis. Enter the magnitude. The radius of the Earth is 6,371 km. The period is one day. m/s2 b. Suppose the Earth were spinning much faster. Find the period that results in the centipetal acceleration being equal to 9.8 m/s?. minutes When the centripetal acceleration equals the acceleration due to gravity, objects are in...
(25 pts) Make a plot of the gravitational magnitude acceleration versus radius for a satellite in Earth orbit. The x-axis should be the orbital radius in units of Earth radii, from Earth's surface, 6,378 km, to 75,000 km. The y-axis should be the computed acceleration in units of m/s2. Be sure to label your plot.
+ -/1 points 0/1 Submissions Used What is the centripetal acceleration of the Earth for a person standing 5600000 m from the axis? The period of rotation of the earth is one day or 86400 seconds centripetal acceleration Does your answer make sense from what you know about standing on the Earth? Should it be a large acceleration or a small acceleration? m/sA2
Earth's radius is 638 x 10^6 m, and it completes one revolution every day. What is the magnitude of the centripetal acceleration of a person standing on the equator?A) 0.00844 m/s^2 B) 0.00343 m/s^2 C) 0.0337 m/s^2 D) 0.343 m/s^2 E) 0.000854 m/s^2
The earth (of radius of 6371km) rotates on itself at a rate of one revolution every 24 hours and is titled by an angle of 23.5°. Let's assume that the earth is a perfect sphere, which allows us to consider a uniform circular motion 23.5 R equator Figure 1: Earth rotation Everybody on earth share the same time of rotation, but based on their location on the earth, they wil have different velocities. A person located in Hawaii, at an...
A body is in an elliptical orbit about the earth. The magnitude
of the acceleration of this body is g (Re/R)^2, where R is the
distance from the body to the center of the earth, Re = 6,370 km,
and g = 9.807 m/s^2 . At the position shown, the speed of the body
is 27,000 km/hr. Determine the rate of change of the speed and the
radius of curvature of the orbit at this position.
9,000 km 12,000 km...
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