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+ -/1 points 0/1 Submissions Used What is the centripetal acceleration of the Earth for a...
a. Compute the centripetal acceleration of a point on the surface of the Earth at the...
a. Compute the centripetal acceleration of a point on the surface of the Earth at the equator caused by the rotation of the Earth about its axis. Enter the magnitude. The radius of the Earth is 6,371 km. The period is one day. m/s2 b. Suppose the Earth were spinning much faster. Find the period that results in the centipetal acceleration being equal to 9.8 m/s?. minutes When the centripetal acceleration equals the acceleration due to gravity, objects are in...
We found the centripetal acceleration of the Earth as it revolves around the Sun. Compute the...
We found the centripetal acceleration of the Earth as it revolves around the Sun. Compute the centripetal acceleration of a point on the surface of the Earth at the equator caused by the rotation of the Earth about its axis. (Enter the magnitude. The radius of the Earth is 6,371 km.) m/s2
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2) towards the...
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2) towards the Earth's axis of a person standing on the surface of the Earth at a latitude of 62.2∘? Recall that latitude is measured from the equator, and assume the Earth's radius is 6,370 km.
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2g=9.8 m/s2) towards...
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2g=9.8 m/s2) towards the Earth's axis of a person standing on the surface of the Earth at a latitude of 78.9∘78.9∘? Recall that latitude is measured from the equator, and assume the Earth's radius is 6,370 km6,370 km.
Suppose a satellite was orbiting the Earth just above the surface. What is its centripetal acceleration?...
Suppose a satellite was orbiting the Earth just above the surface. What is its centripetal acceleration? Smaller thang Equal to 3 Larger than Impossible to say without knowing the mass A hypothetical planet has a mass of half that of the Earth and a radius of twice that of the Earth. What is the acceleration due to gravity on the planet in terms of the acceleration due to gravity at the Earth? The acceleration of gravity on the Moon is...
Earth Mass/Radius: 1 M= 5.97 x 10^24 kg 1 R= 6.38 x 10^6 m Compare th...
Earth Mass/Radius: 1 M= 5.97 x 10^24 kg 1 R= 6.38 x 10^6 m Compare th centripetal force of s 75 kg person standing on the equator of the earth to that of the gravitational force due to the earths rotation. In other words, compute the ratio ( F gravitational/ F centripetal). How many revolutions per day would the earth have to turn to make these forces equal to one another (to makes this ratio exactly 1)?
The earth (of radius of 6371km) rotates on itself at a rate of one revolution every 24 hours and is titled by an angle of 23.5°. Let's assume that the earth is a perfect sphere, which allows us t...
The earth (of radius of 6371km) rotates on itself at a rate of one revolution every 24 hours and is titled by an angle of 23.5°. Let's assume that the earth is a perfect sphere, which allows us to consider a uniform circular motion 23.5 R equator Figure 1: Earth rotation Everybody on earth share the same time of rotation, but based on their location on the earth, they wil have different velocities. A person located in Hawaii, at an...
Today, the Moon’s orbit around Earth has a semi-major axis of a=384,400 km and an orbital...
Today, the Moon’s orbit around
Earth has a semi-major axis of a=384,400 km and an orbital period
of 27.32166 days.
a. The Moon slowly moves outward due to tidal braking of the
Earth’s rotation, and at some future date the Moon will have an
orbital period of 47 days. Compute the semi-major axis of the
Moon’s orbit at this future date (express your answer in
kilometers).
semi-major axis = 5.5*10^5 km
b. Today, the Moon has an angular diameter of...
It takes 23 hours 56 minutes and 4 seconds for the earth to make one revolution...
It takes 23 hours 56 minutes and 4 seconds for the earth to make one revolution (mean sidereal day). What is the angular speed of the earth? The Ang. Speed = 7.29*10^-5 rad/s 1b) Assume the earth is spherical. Relative to someone on the rotation axis, what is the linear speed of an object on the surface if the radius vector from the center of the earth to the object makes an angle of 65.0° with the axis of rotation....
it takes 23 hours 56 minutes and 4 seconds for the earth to make one revolution...
it takes 23 hours 56 minutes and 4 seconds for the earth to make one revolution (mean sidereal day). What is the angular speed of the earth Tries 0/12 Assume the earth is spherical. Relative to someone on the rotation axis, what is the linear speed of an object on the surface if the radius vector from the center of the earth to the object makes an angle of 65.0 with the axis of rotation. The radius of the earth...
a. Compute the centripetal acceleration of a point on the surface of the Earth at the equator caused by the rotation of the Earth about its axis. Enter the magnitude. The radius of the Earth is 6,371 km. The period is one day. m/s2 b. Suppose the Earth were spinning much faster. Find the period that results in the centipetal acceleration being equal to 9.8 m/s?. minutes When the centripetal acceleration equals the acceleration due to gravity, objects are in...
Suppose a satellite was orbiting the Earth just above the surface. What is its centripetal acceleration? Smaller thang Equal to 3 Larger than Impossible to say without knowing the mass A hypothetical planet has a mass of half that of the Earth and a radius of twice that of the Earth. What is the acceleration due to gravity on the planet in terms of the acceleration due to gravity at the Earth? The acceleration of gravity on the Moon is...
The earth (of radius of 6371km) rotates on itself at a rate of one revolution every 24 hours and is titled by an angle of 23.5°. Let's assume that the earth is a perfect sphere, which allows us to consider a uniform circular motion 23.5 R equator Figure 1: Earth rotation Everybody on earth share the same time of rotation, but based on their location on the earth, they wil have different velocities. A person located in Hawaii, at an...
Today, the Moon’s orbit around
Earth has a semi-major axis of a=384,400 km and an orbital period
of 27.32166 days.
a. The Moon slowly moves outward due to tidal braking of the
Earth’s rotation, and at some future date the Moon will have an
orbital period of 47 days. Compute the semi-major axis of the
Moon’s orbit at this future date (express your answer in
kilometers).
semi-major axis = 5.5*10^5 km
b. Today, the Moon has an angular diameter of...
it takes 23 hours 56 minutes and 4 seconds for the earth to make one revolution (mean sidereal day). What is the angular speed of the earth Tries 0/12 Assume the earth is spherical. Relative to someone on the rotation axis, what is the linear speed of an object on the surface if the radius vector from the center of the earth to the object makes an angle of 65.0 with the axis of rotation. The radius of the earth...
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