Calculate the magnitude of your centripetal acceleration due to Earth’s rotation on its axis (standing on the ground here in LA). Why doesn’t this rotation send you flying off the surface of the Earth?
Calculate the magnitude of your centripetal acceleration due to Earth’s rotation on its axis (standing on...
a. Compute the centripetal acceleration of a point on the surface of the Earth at the equator caused by the rotation of the Earth about its axis. Enter the magnitude. The radius of the Earth is 6,371 km. The period is one day. m/s2 b. Suppose the Earth were spinning much faster. Find the period that results in the centipetal acceleration being equal to 9.8 m/s?. minutes When the centripetal acceleration equals the acceleration due to gravity, objects are in...
We found the centripetal acceleration of the Earth as it revolves around the Sun. Compute the centripetal acceleration of a point on the surface of the Earth at the equator caused by the rotation of the Earth about its axis. (Enter the magnitude. The radius of the Earth is 6,371 km.) m/s2
+ -/1 points 0/1 Submissions Used What is the centripetal acceleration of the Earth for a person standing 5600000 m from the axis? The period of rotation of the earth is one day or 86400 seconds centripetal acceleration Does your answer make sense from what you know about standing on the Earth? Should it be a large acceleration or a small acceleration? m/sA2
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2) towards the Earth's axis of a person standing on the surface of the Earth at a latitude of 62.2∘? Recall that latitude is measured from the equator, and assume the Earth's radius is 6,370 km.
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2g=9.8 m/s2) towards the Earth's axis of a person standing on the surface of the Earth at a latitude of 78.9∘78.9∘? Recall that latitude is measured from the equator, and assume the Earth's radius is 6,370 km6,370 km.
The Earth is spinning on its axis. What is your acceleration vector due to your movement with the surface of the Earth? In the Hooke’s law lab, how is the extension of the spring affected by the spinning of the Earth? Answer in centimeters for the largest weight that you used and include the direction of the effect. You can make this question simpler if you pretend we are on the equator. literally this is the question . ( assume...
01. (i) Calculate the centripetal acceleration of the Earth in its orbit around the Sun, (ii) And the net force exerted on the Earth. iii) What exerts this force on the Earth? Assume that the Earth's orbit is a circle of radius 1.5 X 10' m (iv) Calculate the Gravitational Force between the Earth and the Sun. (v) Compare the Gravitational Force to that net force from section (ii) above. Given that F mg (vi) Calculate the acceleration due to...
you stand on a merry go round at a distance of 1.2 m from its axis of rotation. another person standing at a distance of 1.6 m experiences a centripetal acceleration of 3m/s^2. what is your centripetal acceleration?
Calculate the centripetal acceleration of a point 5.9 cm from the axis of an ultracentrifuge spinning at 5.80×104 rev/min. Determine the ratio of this acceleration to that due to gravity. (use scientific notation, e.g. 2.99*10^8)
Calculate the centripetal acceleration of a point 7.4 cm from the axis of an ultracentrifuge spinning at 7.40 × 10 4 rev/min. Determine the ratio of this acceleration to that due to gravity. (use scientific notation, e.g. 2.99*10^8)