A rocket travels horizontally, close to the earth. The centripetal acceleration of the rocket is the earth's gravity (9.8 m/s2). If the earth's radius is 6.3 x 106 m and we neglect air resistance, how fast must the rocket be going to keep a constant height above the earth's surface?
A rocket travels horizontally, close to the earth. The centripetal acceleration of the rocket is the...
a. Compute the centripetal acceleration of a point on the surface of the Earth at the equator caused by the rotation of the Earth about its axis. Enter the magnitude. The radius of the Earth is 6,371 km. The period is one day. m/s2 b. Suppose the Earth were spinning much faster. Find the period that results in the centipetal acceleration being equal to 9.8 m/s?. minutes When the centripetal acceleration equals the acceleration due to gravity, objects are in...
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2) towards the Earth's axis of a person standing on the surface of the Earth at a latitude of 62.2∘? Recall that latitude is measured from the equator, and assume the Earth's radius is 6,370 km.
Suppose a satellite was orbiting the Earth just above the surface. What is its centripetal acceleration? Smaller thang Equal to 3 Larger than Impossible to say without knowing the mass A hypothetical planet has a mass of half that of the Earth and a radius of twice that of the Earth. What is the acceleration due to gravity on the planet in terms of the acceleration due to gravity at the Earth? The acceleration of gravity on the Moon is...
We found the centripetal acceleration of the Earth as it revolves around the Sun. Compute the centripetal acceleration of a point on the surface of the Earth at the equator caused by the rotation of the Earth about its axis. (Enter the magnitude. The radius of the Earth is 6,371 km.) m/s2
At the surface of the earth the acceleration due to gravity is 9.8 m/s2. How far above the surface of the earth would the acceleration due to gravity be 10% smaller? In other words, at what height is the acceleration due to gravity 8.82 m/s2?
A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 49.0 m/s2 . The acceleration period lasts for time 7.00 s until the fuel is exhausted. After that, the rocket is in free fall. Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 m/s2 .
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8 m/s2g=9.8 m/s2) towards the Earth's axis of a person standing on the surface of the Earth at a latitude of 78.9∘78.9∘? Recall that latitude is measured from the equator, and assume the Earth's radius is 6,370 km6,370 km.
How high does a rocket have to go above the Earth's surface until its weight is 0.3 times its weight on the Earth's surface? The radius of the earth is 6.37 x 10^6 m and the acceleration of gravity is 9.8 m/s^2. Answer in units of km.
1. A rocket is launched vertically from the Earth, and the thrust (pushing force) from the engines is directed upward, and has a magnitude of 5.00 x 106 N. The mass of the rocket is initially 2.00 x 105 kg. (a) What is the initial acceleration of the rocket, assuming you can neglect air resistance? (b) After the rocket has been in flight for a while, burning and exhausting a lot of fuel, its mass has decreased to 1.20 x 105 kg, and...
A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 29.4m/s2 . The acceleration period lasts for time 9.00s until the fuel is exhausted. After that, the rocket is in free fall. Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 m/s2 . Write your answer numerically in units of meters.