a.)
Since, velocity(V) = (total distance travel(d))/(total taken time(t))
for first half,
given d1 = distance travel in first half trip = 4,139 m
t1 = time taken in first half trip = 180 sec.
So,
V1 = 4139/180
V1 = 22.99 m/sec.
(b.)
for entire trip,
Vavg = (d1 + d2)/(t1 + t2)
here, d2 = distance travel in return trip = d1 =4139 m
t2 = time taken in return trip = 165 sec.
So, Vavg = (4136 + 4136)/(180 + 165)
Vavg = 23.98 m/sec.
Please upvote.
A race car traveling northward on a straight, level track at constant speed travels 4,139 m...
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it's a question from my physical science course,
unfortunately it's not a subject option.
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