Pb(NO3)2 + 2NaCl ----> PbCl2 + 2 NaNO3
Molarity = (mass/molarmass)*(1000/V in mL)
mass of PbCl2 = 14.12 g
molarmass of PbCl2 = 278.1 g/mol
moles of PbCl2 = mass/molarmass
= (14.12/278.1)
= 0.0508 moles
From the balanced equation:
moles of PbCl2 = moles of Pb(NO3)2
Molarity of Pb(NO3)2 = moles*(1000/V in mL)
= 0.0508*(1000/200)
= 0.254 M
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