Question

Problem 5. (20 pts) A vertical propane tank with an outside diameter of D 300 mm and a wall-thickness of t-9 mm is subjected to a horizontal force of P 41 kN. The gage pressure inside the tank is 7 MPa. [D-300 mm, te9 mm, P 41 kN] a) Determine the maximum normal stress at point K b) Determine the shear stress produced by the applied force. c) Determine the maximum shear stress in the 3d stress element.

Answer 1

Data missing height of Location of points is not mentioned. These calculations can be used to same extant. Normal stress at H = sigma_N = Force/c/s area = 41 times 10^3/4/pi {300^2 - 282^2} = 5 N/mm^2 tau = 5 MPa bz - Shear stress due to applied force: - S F_EM = 41 kN c/s area = pi/4 (300^2 - 282^2) = 8227.83 mm^2 sigma_max (Normal) = P_i/2 + squareroot (P_i/2)^2 + tau^2 = 7/2 + squareroot (7/2)^2 + (5) a = sigma_Max (N) = 9.6 N/mm^2 c: Maximum shear stress (tau_Max): - T = 41 times (0.18) = 6.15 kN middot m I_p = pi/32 {300^4 - 282^4} = R = D/2 = 300 /2 = 150 mm T/I_p = (q_Max = tau_xy)/R (q_Max = tau_xy)/R = 6.15 times 10^6 times 150/pi/32 (300^4 - 282^4) tau_xy = 5.3 N/mm^2