Question

Determine the empirical and molecular formulas of each of the following substances.

a. Styrene, a compound substance used to make Styrofoam^® cups and insulation, contains 92.3% C and 7.7% H by mass and has a molar mass of 104 g/mol.

b. Caffeine, a stimulant found in coffee, contains 49.5% C, 5.15% H, 28.9% N, and 16.5% O by mass and has a molar mass of 195 g/mol.

c. Monosodium glutamate (MSG), a flavor enhancer in certain foods, contains 35.51% C, 4.77% H, 37.85% O, 8.29% N, and 13.60% Na, and has a molar mass of 169 g/mol.

Answer 1

Ams -@ h tompund otans 923%c, 9% H mao f th compeund- 1049/md mam purcmt, t malar onniut tho starlnp malirial Ceaving Suncs anu we wae Cowetaiy pancat ompaion x 100 1 anto grams 92.3 = 92.3 mam 1 mam No os ofydrog = .63 92.9 m mus c= .68 mol c 12.01 Dwdnp te maluunlue olaus lay the sinaluat munlow 2.68 - 1.006= I. 469 me ato C: H 1 Jhus The empineal fov mula n empirical frmala CH 12.01 t 1.O08 mam 11 - 13.016 9

We have, msleaular frmula ompuneal fomda Saw mam Cinprical formula man 104 91ms) Bint 1 13.018 2.99 mlealar frimla the camporund Lanse ompond contans 4 , 5.1s% H, a8.9% N and 16. 5%0. Inslan mam 1959 m) 49.5 x 100 mam 15 IN mam H mam 10 (6.5 -7 16. 7 In Now, mdlus C 49.5 =4.12 me) 12.01 = .10 mle

of 2.04 ms) N: 14.006 melas of 0 16.5 ms-1.0 Dwidling the mle mlue lon smallol mlan otain, we 2.06 4.12 E 4 1.02 = 2 and 03-1 1.02 5.10 :4.965, 1.05 1.09 Thuo, c:H: N:0 4:2:I Th ompinical fmla s No mpirical fomala S(Ax 12.01+Sxl.08 +2x14.006 +IS9 mam 97.05 9ms) mlar mam = 195 molan mam have , n We emprical fnmula man ms)

maeealan fomuda Thae melsadlaw frimalea mx emprical famula the ompond s 2 Ans Th umpoum onlauns 25.51% c,4.39% H, .85% 00.29'%N and 1. 60% Na C= 35.51 mam x 1001 35-51 4999 100 4.37 mam 100 mam D X 1 00 3.29 mam of N 0829 =12, 60 1 Na .60 mam 35.5/ md2.9s mdl Now, mus of 12.01 4.9 md4.3 ma) 1UD8 mols of H 8.29 N o 14.006 Bob0 mel mles of Na- 0.59 md) 22.99 D wrdinp tre male al loy smallot numb Botain we

2.95 0.S9 4.99 239 4 0.59 D.S9 1 0.59 0.59 0 59 Jhe satis of CH:0;N; Na :8:4:11 The omprical famdlo in cs N Na Empuneal fomula Gx1201+ 6x 1.008 +4xi59 +14.006 +22.99)m) 169.06 g/mo molan mam = 1G9 g/mdl molan mam empini cal frmula mam 169 gIma 169.06 g/ml) The mdlealar frmala n (sH0 N Na L