In a 100 g sample of the compound, there are 10.13 g of C and 89.87 g of Cl. Therefore, in a 100 g sample, there are
and
Therefore, the ratio of Cl to C in a sample of the compound is
which is close enough to 3. Thus, the empirical formula of the compound is CCl3. The molar mass of the compound is 237 g/mol. The molar mass of CCl3 is 118.37 g/mol. 237 g/mol is roughly double the molar mass of CCl3. Just multiply the coefficients of the empirical formula by 2 and you get the chemical formula of the compound, CCl6.
Hope this helps!
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