The density of an unknown element in the gaseous state is 1.60 g at 300 K and 1 atm. Which of the following could be th...
a. He
b. Ne
c. Ar
d.O2
e. Cl2
Homework Answers
Ideal gas equation PV = nRT
P = 1 atm
T = 300 K
Concentration = n/V = P/RT
= 1/(0.08206 x 300) = 0.04062 mol/L
Since density = 1.60 g/L
Mass of 0.04062 mol of element = 1.60 g
Molar mass = mass/moles
= 1.60/0.04062 = 39.4 g/mol
Thus the unknown element is c. Ar
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