Molar mass of Ne = 20.18 g/mol
mass(Ne)= 2.2 g
use:
number of mol of Ne,
n = mass of Ne/molar mass of Ne
=(2.2 g)/(20.18 g/mol)
= 0.109 mol
Given:
P = 488.0 torr
= (488.0/760) atm
= 0.6421 atm
V = 3.7 L
n = 0.109 mol
use:
P * V = n*R*T
0.6421 atm * 3.7 L = 0.109 mol* 0.08206 atm.L/mol.K * T
T = 266 K
Answer: 266 K
At what temperature will a 2.2 g sample of neon gas exert a pressure of 488...
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