Question

chapter question

a) If 0.00954 mol neon gas at a particular temperature and pressure occupies a volume of 219 mL, what volume would 0.00784 mol neon occupy under the same conditions?

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b)If 2.77 g of argon gas occupies a volume of 4.29 L, what volume will 1.28 mol of argon occupy under the same conditions?

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c)What mass of neon gas is required to fill a 4.81-L container to a pressure of 1.39 atm at 27°C?

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Answer 1

(a Avogadro's law states that Equal volume of gas have egne no of moles at constant & pressure wat sonrlar DA Volume of gas is directly proportional to no of moles of ges at constant temperature of of pressure van na no of mole. = constant V &V n ontlar M. = 2lgail " 0.00954 mol n2= 0.00784 219 0.00954 -0.007841 VF 2194 0.00784 0.00954 SEE = 179.9ml 100 ml i 1.80 x 102ml

molar mans of Argon= molemas olen mars 40g/mol n=2.17 -0.069.25 Vi= 4.290. 125 1.28 mol V₂ = V, n reds of ? ou = 4.29x 9.28 ni 0-06925 al = 79.3 l on Ideal gas conditions PV=nRJ wod p. 1.39 alai V 4.014 n =? R = 0.0021 latum mol-'k- T= 27°C = 27+273=300k na PV = 1-39% 4.01 -0.27 RT 0.0821x300 mass = nx molar massan 0.27 mot & 20g, al 5.48g